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14x^2+29x^-1-15=0
We add all the numbers together, and all the variables
14x^2+29x-16=0
a = 14; b = 29; c = -16;
Δ = b2-4ac
Δ = 292-4·14·(-16)
Δ = 1737
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1737}=\sqrt{9*193}=\sqrt{9}*\sqrt{193}=3\sqrt{193}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-3\sqrt{193}}{2*14}=\frac{-29-3\sqrt{193}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+3\sqrt{193}}{2*14}=\frac{-29+3\sqrt{193}}{28} $
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